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	<title>Comments on: The Two Envelopes Problem</title>
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		<title>By: Philip Brocoum</title>
		<link>http://oscarbonilla.com/2009/10/the-two-envelopes-problem/comment-page-1/#comment-11697</link>
		<dc:creator>Philip Brocoum</dc:creator>
		<pubDate>Wed, 07 Oct 2009 13:18:01 +0000</pubDate>
		<guid isPermaLink="false">http://oscarbonilla.com/?p=280#comment-11697</guid>
		<description>There actually isn&#039;t any flaw in how I worded the problem. Watch: I fill one envelope with $10, another with $20, and then give you the $20 envelope. I then tell you that my envelope contains either double or half the amount of money that&#039;s in yours. There, what&#039;s the problem? Setting up the problem is easy.

The reason this problem is controversial is because it&#039;s TRICKY, and people hate it when they are tricked. Here is another similarly tricky problem: A couple has two children, one of whom is a boy. What is the probability that the other child is also a boy? The answer is a counterintuitive 1/3 because the problem does not state WHICH child is a boy. If the problem had instead stated, &quot;the first child is a boy,&quot; then the answer would be the expected 1/2.

Of course, when you explain that to people, they get mad and say, &quot;Well, you tricked me! It&#039;s an unfair question. You didn&#039;t say which child was the boy, so I assumed it was the first one.&quot; Exactly, you cannot make unfounded assumptions. That&#039;s what the riddle is trying to teach you.

Likewise, the two envelopes problem is a lesson on symmetry. It&#039;s TRICKY because people don&#039;t realize that BOTH envelopes contain either double or half what&#039;s in the other. It&#039;s a symmetrical statement. Even if you reason yourself into switching envelopes, once you&#039;ve switched it then turns out that my envelope STILL contains either double or half what&#039;s in your envelope, so by your reasoning you should switch again. Which is, of course, ridiculous.

People like to complain, &quot;It&#039;s an unfair question. I thought you meant that my envelope was filled first with a constant value of $100, and then yours contains either $200 or $50.&quot; Of course, that&#039;s not what the problem says, and people are making unfounded assumptions.

Also, the incorrect solution that you are talking about, solution 1 on my site, was included on purpose specifically because it&#039;s wrong. I was turning the riddle into one of those, &quot;Here&#039;s a proof that 1 + 1 = 3, where is the error?&quot; type of problems.</description>
		<content:encoded><![CDATA[<p>There actually isn&#8217;t any flaw in how I worded the problem. Watch: I fill one envelope with $10, another with $20, and then give you the $20 envelope. I then tell you that my envelope contains either double or half the amount of money that&#8217;s in yours. There, what&#8217;s the problem? Setting up the problem is easy.</p>
<p>The reason this problem is controversial is because it&#8217;s TRICKY, and people hate it when they are tricked. Here is another similarly tricky problem: A couple has two children, one of whom is a boy. What is the probability that the other child is also a boy? The answer is a counterintuitive 1/3 because the problem does not state WHICH child is a boy. If the problem had instead stated, &#8220;the first child is a boy,&#8221; then the answer would be the expected 1/2.</p>
<p>Of course, when you explain that to people, they get mad and say, &#8220;Well, you tricked me! It&#8217;s an unfair question. You didn&#8217;t say which child was the boy, so I assumed it was the first one.&#8221; Exactly, you cannot make unfounded assumptions. That&#8217;s what the riddle is trying to teach you.</p>
<p>Likewise, the two envelopes problem is a lesson on symmetry. It&#8217;s TRICKY because people don&#8217;t realize that BOTH envelopes contain either double or half what&#8217;s in the other. It&#8217;s a symmetrical statement. Even if you reason yourself into switching envelopes, once you&#8217;ve switched it then turns out that my envelope STILL contains either double or half what&#8217;s in your envelope, so by your reasoning you should switch again. Which is, of course, ridiculous.</p>
<p>People like to complain, &#8220;It&#8217;s an unfair question. I thought you meant that my envelope was filled first with a constant value of $100, and then yours contains either $200 or $50.&#8221; Of course, that&#8217;s not what the problem says, and people are making unfounded assumptions.</p>
<p>Also, the incorrect solution that you are talking about, solution 1 on my site, was included on purpose specifically because it&#8217;s wrong. I was turning the riddle into one of those, &#8220;Here&#8217;s a proof that 1 + 1 = 3, where is the error?&#8221; type of problems.</p>
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